(5x^4-3x^2+4)/(x^2+2)

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Solution for (5x^4-3x^2+4)/(x^2+2) equation:


D( x )

x^2+2 = 0

x^2+2 = 0

x^2+2 = 0

1*x^2 = -2 // : 1

x^2 = -2

x in (-oo:+oo)

(5*x^4-(3*x^2)+4)/(x^2+2) = 0

(5*x^4-3*x^2+4)/(x^2+2) = 0

(5*x^4-(3*x^2)+4)/(x^2+2) = 0 // * x^2+2

5*x^4-(3*x^2)+4 = 0

5*x^4-3*x^2+4 = 0

t_1 = x^2

5*t_1^2-3*t_1^1+4 = 0

5*t_1^2-3*t_1+4 = 0

DELTA = (-3)^2-(4*4*5)

DELTA = -71

DELTA < 0

x belongs to the empty set

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